simple projectile motion problems with solutions

#Simple projectile motion problems with solutions how to

Here is how to find the maximum height of the tennis ball The time it takes to reach the maximum heightĪ. Problem 3Ī tennis ball is thrown vertically upwards from the front with a velocity of 50 m/s. Therefore, the bullet will cover 120 meters from the foot of the building to the ground. Horizontal velocity = Initial velocity = u x = 40 m/s How far from the feet of the building will the bullet be assumed to touch the ground? (Take the gravitational acceleration, g = 10 m/s 2). Problem 2Ī bullet is fired horizontally with a velocity of 40 meters per second from the top of a building 50 meters high. Therefore, the range of the stone shot out of the catapult is 365.885 meters. Here is the formula that will help us find the range Therefore, our maximum height is 158 meters. Our maximum height can be approximated into The maximum height, H max = (65 2sin 260 0) / 2 x 10 We can now substitute our formula with the data

Maximum height, H max = (u 2sin 2θ) / 2g Solution The formula for calculating the maximum height is Here is how to calculate the maximum height Therefore, the time of flight is 11.3 secondsī. We will now insert our data into the above formula The formula for solving a problem on time of flight, T is (2usinθ) / g Solution

To find the time of the flight, we will apply the following methods: A stone is shot out from a catapult with an initial velocity of 65 meters per second at an elevation of 60 degrees.

Simple projectile motion problems with solutions